Firstly, what is a filesystem block?
It is the smallest piece/size of the disk allocated or accessible on the filesystem.
Can you explain a bit more?
Having a larger block size helps in achieving better performance due to lesser number of disk reads and lower metadata overhead. However, it is a disadvantage for files of smaller size. For example, assuming block size of 8 KB, 8 KB is allocated even if the file size is only 1 KB.
Tell me how do I find the filesystem block size on Solaris?
There’re couple of ways:
It is the smallest piece/size of the disk allocated or accessible on the filesystem.
Can you explain a bit more?
Having a larger block size helps in achieving better performance due to lesser number of disk reads and lower metadata overhead. However, it is a disadvantage for files of smaller size. For example, assuming block size of 8 KB, 8 KB is allocated even if the file size is only 1 KB.
Tell me how do I find the filesystem block size on Solaris?
There’re couple of ways:
- From “df -g”; example:
df -g | grep "block size" | awk '{print $1 " " $4}' - From “fstype –v”; example:
fstyp -v /dev/dsk/c0t1d0s0 | grep ^bsize
2 comments:
There are some "smart quotes" in the first command that need to be converted to regular quotation marks.
Thank you for the keen observation. The quotes are fixed now.
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